2x^2-20x-150=0

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Solution for 2x^2-20x-150=0 equation:



2x^2-20x-150=0
a = 2; b = -20; c = -150;
Δ = b2-4ac
Δ = -202-4·2·(-150)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*2}=\frac{-20}{4} =-5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*2}=\frac{60}{4} =15 $

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